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The 128 bit address of the IPv6 is divided into 16 bit boundaries. Each of these boundaries is converted to a 4 digit hexadecimal (base 16) number which is separated by colons.

Examples:

    •Here's an IPv6 address (128 bit) in binary form:
    001000011101101000000001101001100000000000000000010111100111011
    000000101010101000000001111111111111110001010001001110001011010

    •We divide it into 16 bit boundaries:
    0010000111011010 000000011010011 0000000000000000 0010111100111011
    0000001010101010 000000011111111 1111111000101000 1001110001011010

    •Each of these 16 bit boundaries is converted to hexadecimal (base 16) and delimited with colons:
    21DA : 00D3 : 0000 : 2F3B : 02AA : 00FF : FE28 : 9C5A

    •Leading zeros are suppressed. However, there must be at least one single digit in each boundary:
    21DA:D3:0:2F3B:02AA:FF:FE28:9C5A


got feedback?
Re. IPv6 Address Syntax (#10289) examples: The second and sixth binary boundaries (000000011010011 and 000000011111111, respectively) are each only 15 bits long.

2009-10-29 16:00:49


I think you've missed two bits./PeterB

2009-07-06 10:57:33


by david987 See Profile edited by Optimized See Profile
last modified: 2004-08-18 07:13:11


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