karlmarx
join:2006-09-18
iraq
 ·Fairpoint Communic..
| well, considering in general terms, the radio distance is defined as O(ptical) = sqrt(2h(r))+sqrt(2h(t)), where O = distance to optical horizon, and h=(r)receiver height, and h(t) is transmitter height. So assume the antenna is 20' at both sides. The optical distance would be approximately sqrt(2*20) + sqrt(2*20) = Appx 12.5 miles.
Now we calculate the loss.
PL = 117 + 20log10fMhz-20log10hthr+40Log10D
Where 117 = Constant
2.4Ghz
20' and 20'
Distance of 12 miles
So it's about 175db loss over that distance. Thus, the antenna is the key, because with a 175db loss, the antenna is going to have to be pretty tight.
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