 JTCAlways Mount A Scratch Monkey
join:2002-01-09
USA | said by mcnet:that would be a /112 i believe (each 4 symbols = 16 bits, 128-16=112) Doh, I think I grok...
So given the address of 2001:0ded:bef5:0dc6:0000:0000:0078:eeee, /112 would make 2001:0ded:bef5:0dc6:0000:0000:0078 the 'subnet', with the 0078 part the entry that changes to identify the different subnets and the eeee part for each machine.
BTW, I tried the /48 approach and it's working, thanks for the pointer. Now to try and figure out if a DHCPv6 server and DHCPv4 can coexist on the same network without banging heads and get bind set up to deal with ip6 as well.
Thank you for the help and info so far, it is appreciated!
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All hardware sucks, all software sucks, some just suck more than others |
