 inGearX3.1415 9265
join:2000-06-11
New York | physics + math... help me figure this out... Objective - what deep sea fishing line should I order?
2000 meter fishing line with tension of
like
quote:
$59.99
MAXX POWER PRO BRAID Fishing Line g 2000M 100LB DYNEEMA
»www.ebay.com/itm/MAXX-POWER-PRO-···211c7409
OR
quote:
$126.59
Braid Fishing Line 2000m 125LB 57kg 0.6mm GR x-strong
»www.ebay.com/itm/Braid-Fishing-L···b82a4e22
OR ETC...
and if I need 10+ lines can be a good price difference...
SO DETAILS:
if I want to fill up a regular balloon with helium and tie it to a fishing line
how much tension / vertical pull does that create?
how do we calculate this?
how much lighter then air is helium? (this is due to be done in Nevada desert)
+ volume of a regular / average balloon
what degree does the ambient temperature play? doing this during mid day (hot + sunshine [I guess color of balloons will play a role [black keeping the heat and doing what to the helium?]) or sunset or night (cold)?
Also each balloon will get a "finger light" inside of it
»www.ebay.com/sch/i.html?_nkw=fin···70.l1313
weight is (not sure of exact model - but will find out) but I think 4.6 grams
so that creates a pull downwards... (decreases the vertical upwards pull of a balloon and the tension)
- as the more and more balloons are added - there is more and more stress on the line at the bottom - to hold it to the bottom
+ there is a factor of wind and tension that it creates... can be a critical factor... calculation of this can be interesting (how much tension would be created by 10 MPh wind blowing on 100 balloons?) and vital
Now this doesn't need to be exact rocket since (it's not a rocket with people in it - and if the line rips it is OK - so we do not need to go into absolute minor factors...)
but a rough estimate so I do not spend $5000 when I can spend $2500 or so...
Per this page I found that
quote:
8.3 grams of lift per 8.2 liters of helium [I think average balloon]
»www.cockeyed.com/science/helium/helium.shtml
thus 100 balloons would create a vertical pull of 830 grams - [100*4.3 gram finger lights] = 400 grams of tensions at the base
while 1000 balloons would create 4 Kilos of tension
making it easy for most lines to handle
Hmmmmm now what about the wind? what does 10 MPh wind do to the tension?
what other factors are involved? I am sure I am forgetting something...
now there can be a _bonus_ at the bottom of the line I want to attach a rescue party super bright flare - or so - working on that here... »extremely bright flare?
what else am I forgetting?
thank you... |
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 cdruGo ColtsPremium,MVM
join:2003-05-14
Fort Wayne, IN
kudos:5 | I'd go with ASP.Net with a MS-SQL database. |
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 ProtusMoseImmortal. Eternal.Premium
join:2001-10-03
Bellevue, NE
kudos:4 | reply to inGearX
You could write an applet to process that, I suppose. |
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| reply to inGearX
42 |
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cdruGo ColtsPremium,MVM
join:2003-05-14
Fort Wayne, IN
kudos:5 | reply to inGearX
Wrong forum aside, what is your end objective? |
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inGearX3.1415 9265
join:2000-06-11
New York | said by cdru:Wrong forum aside, what is your end objective?
well where should I post this?
I imagine we like to solve puzzles or so here  |
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 darciliciousCyber LibrarianPremium
join:2001-01-02
Forest Grove, OR
kudos:1
 ·Frontier FiOS
| said by inGearX:I imagine we like to solve puzzles or so here
Only if they involve web technologies  |
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 gorrillamcdWell, that was interesting.
join:2010-04-01
mexico
1 edit | reply to inGearX
I don't think there are any specific physics forums here on dslreports, but I found this one googling: »www.physicsforums.com
If you post there, a couple of pointers:
1. Make sure they know this is for a real project and not you being lazy on your homework. Most places I've seen like that look down on doing your homework for you.
2. Use correct units when you are doing your math. It helps immensely in understanding what's actually going on in a formula. For force, you would use newtons, which is 1 kg*m/s^2. It's derived from the formula Force=mass*acceleration. Grams are mass, not force. Pounds, I believe, are a unit of force that take the acceleration of gravity (9.8 m/s^2) as a given.
3. If the fishing line is directly vertical, your math is right, though you're probably missing some variables (wind speed, weight of the balloons themselves, etc...).
4. If you decide to account for wind, the math gets only slightly more complicated (you have to use some trigonometry, but's it's not bad). PM me if you'd like.
--
I'm an IT technician with a lot to learn, taught by viewers like you! |
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| reply to cdru
said by cdru:Wrong forum aside
He is hoping people won't remember he is supposed to be in Somalia of some such crap. |
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