| ip address I need to do this homework and I am confused how to do it?
Please can someone help me.
1. You are asked to design a network for a medium-class company. The company decides to use the 10.0.0.0 private IP address. The network will span six buildings with a router in each building to join the networks. Currently, the company has approximately a total of 1,000 workstations in the following locations:
• Building 1,200 workstations
• Building 2,125 workstations
• Building 3,135 workstations
• Building 4,122 workstations
• Building 5,312 workstations
• Building 6,105 workstations
Design a simple addressing solution that leaves ample room for growth and is easy to administer. Explain what happens to your design if the number of hosts per network jumps to over 1,024 per building.
Thanks sol |
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 AnavSarcastic Llama? Naw, Just AcerbicPremium
join:2001-07-16
Dartmouth, NS
kudos:3 | |
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 cdruGo ColtsPremium,MVM
join:2003-05-14
Fort Wayne, IN
kudos:7 | reply to Sol
Simplest answer is to leave the routers in their boxes and just wire everything up for a /8 subnet. Yeah your network probably will be somewhat crippled by all the broadcast traffic, but it's the simplest. 
Alternatively, you might want to assign a subnet per building. Hint: Choose something a bit smaller than a /8.
As to the question what happens when the number of hosts per network jumps to over 1024 per building, I would answer that by saying "The exact same thing that happens when you exceed 1022 and 1023 hosts per building." The question can't be answered as the network settings haven't been defined. You can assume things, but we know what happens when you do that. |
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| reply to Sol
This will help.
»www.subnet-calculator.com/ |
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| reply to Sol
Hi Sol,
What they're asking you to do is to subnet the network, and to plan each subnet so that there is room for growth. This is an exercise that network engineers at ISPs and large corporations do every day.
What you want to do is look at each building, and find a subnet with enough hosts to support that building, plus say...50% growth. a 10. Class A network is a /8 meaning you can use anything from 10.0.0.0-10.255.255.255 (remember that you need network and broadcast addresses). So you'd want to subnet that into smaller blocks, say 10.0.0.0 /21 (10.0.0.0-10.0.7.255 -2046 hosts) for building 1.
That wouldn't work for building 2, so you'll need a bigger block for it. I'd start with building 6, and get the biggest subnet for that, then use smaller subnets for each successively smaller building. A smart engineer, would also include a subnet (/30 or /31) for each link between each building.
Good luck! Subnetting can seem overwhelming at first, but once you get the hang of it, it's easy. As switchman said, go to a subnet calculator site, and look at how the hosts change, when you use different mask sizes. Wikipedia also has a good article on subnetting. |
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| reply to Sol
Also, here's a tip that helped me learn subnetting:
Each added subnet bit halves the number of IPs in a subnet.
Lets start with a /24 mask. It's common and a good starting point for most subnetting exercises.
A /24 is 255.255.255.0, and contains 256 addresses (There are 254 hosts available since you need to take away 1 IP for the network address, and 1 IP for the broadcast address).
If we add a bit, it's a /25 and that's 255.255.255.128. you masked off half of the available IPs (128-255), or split your /24 in half (whatever is easier to visualize.
If you go the other way, and remove a bit, you have a /23 that's 255.255.254.0. that doubles the IPs available to 512 addresses (510 host).
so...
/24=256
/23=512
/22=1024
/21=2048
/20=4096
/19=8192
/18=16384
I use /24 in my brain because it's a octal number, and as you'll notice, most things in the networking world are based on the number 8. Get used to counting in multiples of 8 (and then subtracting 2), and you'll be subnetting in your head.
Hope this helps! |
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cdruGo ColtsPremium,MVM
join:2003-05-14
Fort Wayne, IN
kudos:7 | reply to cablegeek01
said by cablegeek01:So you'd want to subnet that into smaller blocks, say 10.0.0.0 /21 (10.0.0.0-10.0.7.255 -2046 hosts) for building 1. First thing, the OP message formatting is confusing. I made the same mistake at first that you did. Building 1 has 200 workstations, not 1,200 workstations as shown. There should be a space after the comma.
Regardless, 2046 allowable hosts in a subnet is technically possible, although would be a very poor practice especially for a workstation environment. The biggest issue is that the broadcast traffic likely will significantly detrimental effect if not completely cripple the network. |
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| Doh! I agree. Anything more than a /22 is asking for issues. That's the problem with a lot of courses, they're simply looking for the math to subnet, and not taking into account the issues with large broadcast domains. A better exercise would entail small offices with /24 to /29 needs.
maybe they're looking for VLANs and inter VLAN routing to mix it up a bit???  |
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AsherN
join:2010-08-23
Thornhill, ON | reply to Sol
I'd keep things somply and go:
10.1.0.0/22
10.2.0.0/22
10.3.0.0/22
10.4.0.0/22
10.5.0.0/22
10.6.0.0/22
Consistent addressing scheme, building # built in the scheme. |
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| reply to cdru
Thanks, it is making more sense now.
Sol |
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| reply to cablegeek01
Yes, it helps a lot and thanks for the tip.
Sol |
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| reply to AsherN
Thank to all it really help me a lot. |
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| reply to cablegeek01
Thanks for helping, really appreciate.
Sol |
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| reply to cablegeek01
Thanks for helping, really appreciate.
Sol |
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